Shelby Township, Ripley County, Indiana
Township in Indiana, United States / From Wikipedia, the free encyclopedia
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Shelby Township is one of eleven townships in Ripley County, Indiana. As of the 2020 census, its population was 1,038 (up from 999 at 2010[3]) and it contained 373 housing units.[4]
More information Census, Pop. ...
Census | Pop. | Note | %± |
---|---|---|---|
1890 | 2,365 | — | |
1900 | 2,387 | 0.9% | |
1910 | 2,182 | −8.6% | |
1920 | 1,995 | −8.6% | |
1930 | 1,569 | −21.4% | |
1940 | 1,665 | 6.1% | |
1950 | 801 | −51.9% | |
1960 | 881 | 10.0% | |
1970 | 830 | −5.8% | |
1980 | 901 | 8.6% | |
1990 | 853 | −5.3% | |
2000 | 867 | 1.6% | |
2010 | 999 | 15.2% | |
2020 | 1,038 | 3.9% | |
Source: US Decennial Census[5] |
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Quick Facts Country, State ...
Shelby Township | |
---|---|
Coordinates: 38°58′19″N 85°22′34″W | |
Country | United States |
State | Indiana |
County | Ripley |
Government | |
• Type | Indiana township |
Area | |
• Total | 69.39 sq mi (179.7 km2) |
• Land | 69.11 sq mi (179.0 km2) |
• Water | 0.27 sq mi (0.7 km2) |
Elevation | 912 ft (278 m) |
Population (2020) | |
• Total | 1,038 |
• Density | 15/sq mi (5.8/km2) |
Area code | 812 |
FIPS code | 18-69264[2] |
GNIS feature ID | 453845 |
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