Mockingbird Valley, Kentucky
City in Kentucky, United States / From Wikipedia, the free encyclopedia
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Mockingbird Valley is a home rule-class city in Jefferson County, Kentucky, United States.[1] Since incorporation, there has been some interest in making it a historic preservation district, largely to prevent unwanted development. The population was 167 at the 2010 census.[4] It has the highest per capita income of any location in Kentucky and the tenth-highest of any location in the United States.[citation needed]
Mockingbird Valley, Kentucky | |
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Coordinates: 38°16′12″N 85°40′54″W | |
Country | United States |
State | Kentucky |
County | Jefferson |
Incorporated | c. 1940[1] |
Area | |
• Total | 0.21 sq mi (0.54 km2) |
• Land | 0.21 sq mi (0.54 km2) |
• Water | 0.00 sq mi (0.00 km2) |
Elevation | 502 ft (153 m) |
Population (2020) | |
• Total | 175 |
• Density | 845.41/sq mi (326.48/km2) |
Time zone | UTC-5 (Eastern (EST)) |
• Summer (DST) | UTC-4 (EDT) |
ZIP Code | 40207 |
FIPS code | 21-52842 |
GNIS feature ID | 2404279[3] |
Located directly to the east of Louisville along the Ohio River, Mockingbird Valley is frequently referred to as a "country enclave" and is noted for its rural feel. It is located on river bluffs and rolling hills, with large homes set back from the road, heavy tree density, bridges and walls using traditional local materials, as well as undisturbed rock outcroppings. One-third of the roads are privately owned, and the entire city is zoned residential except for a small commercial parking lot.