Hoseason Island
Island in Antarctica / From Wikipedia, the free encyclopedia
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Hoseason Island (63°44′S 61°41′W) is an island 6 nautical miles (11 km; 6.9 mi) long and 3 nautical miles (5.6 km; 3.5 mi) wide, lying 20 nautical miles (37 km; 23 mi) west of Trinity Island in the Palmer Archipelago, Antarctica.[1]
Quick Facts Geography, Location ...
Geography | |
---|---|
Location | Palmer Archipelago, Antarctica |
Coordinates | 63°44′S 61°41′W |
Archipelago | Palmer Archipelago |
Length | 11.112 km (6.9047 mi) |
Width | 5.556 km (3.4523 mi) |
Highest elevation | 495 m (1624 ft) |
Highest point | Stopford Peak |
Administration | |
Administered under the Antarctic Treaty System |
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