Hopkinton, Iowa
City in Iowa, United States / From Wikipedia, the free encyclopedia
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Hopkinton is a city in Delaware County, Iowa, United States.[1] The population was 622 at the time of the 2020 census.[4]
Quick Facts Country, State ...
Hopkinton, Iowa | |
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Coordinates: 42°20′38″N 91°14′55″W[1] | |
Country | United States |
State | Iowa |
County | Delaware |
Incorporated | March 3, 1874 [2] |
Area | |
• Total | 0.64 sq mi (1.66 km2) |
• Land | 0.64 sq mi (1.66 km2) |
• Water | 0.00 sq mi (0.00 km2) |
Elevation | 860 ft (260 m) |
Population (2020) | |
• Total | 622 |
• Density | 968.85/sq mi (374.02/km2) |
Time zone | UTC-6 (Central (CST)) |
• Summer (DST) | UTC-5 (CDT) |
ZIP code | 52237 |
Area code | 563 |
FIPS code | 19-37155 [1] |
GNIS feature ID | 0457659 [1] |
Website | hopkintoniowa |
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