Fremont Township, Steuben County, Indiana
Township in Indiana, United States / From Wikipedia, the free encyclopedia
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Fremont Township is one of twelve townships in Steuben County, Indiana, United States. As of the 2020 census, its population was 2,851, down from 2,993 at the 2010 census,[4] and it contained 1,211 housing units.
Quick Facts Country, State ...
Fremont Township | |
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Coordinates: 41°44′02″N 84°55′03″W | |
Country | United States |
State | Indiana |
County | Steuben |
Government | |
• Type | Indiana township |
Area | |
• Total | 23.15 sq mi (60.0 km2) |
• Land | 22.94 sq mi (59.4 km2) |
• Water | 0.21 sq mi (0.5 km2) 0.91% |
Elevation | 1,070 ft (326 m) |
Population | |
• Total | 2,851 |
• Density | 130.5/sq mi (50.4/km2) |
Time zone | UTC-5 (Eastern (EST)) |
• Summer (DST) | UTC-4 (EDT) |
ZIP code | 46737[3] |
Area code | 260 |
GNIS feature ID | 453317 |
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