Cass Township, Ohio County, Indiana
Township in Indiana, United States / From Wikipedia, the free encyclopedia
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Cass Township is one of four townships in Ohio County, Indiana, United States. As of the 2020 census, its population was 694 and it contained 311 housing units.[1]
More information Census, Pop. ...
Census | Pop. | Note | %± |
---|---|---|---|
1890 | 701 | — | |
1900 | 615 | −12.3% | |
1910 | 591 | −3.9% | |
1920 | 535 | −9.5% | |
1930 | 523 | −2.2% | |
1940 | 520 | −0.6% | |
1950 | 506 | −2.7% | |
1960 | 447 | −11.7% | |
1970 | 398 | −11.0% | |
1980 | 481 | 20.9% | |
1990 | 546 | 13.5% | |
2000 | 649 | 18.9% | |
2010 | 714 | 10.0% | |
2020 | 694 | −2.8% | |
Source: US Decennial Census[2] |
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Quick Facts Country, State ...
Cass Township | |
---|---|
Coordinates: 38°55′53″N 84°59′22″W | |
Country | United States |
State | Indiana |
County | Ohio |
Government | |
• Type | Indiana township |
Area | |
• Total | 18.54 sq mi (48.0 km2) |
• Land | 18.54 sq mi (48.0 km2) |
• Water | 0 sq mi (0 km2) 0% |
Elevation | 830 ft (253 m) |
Population (2020) | |
• Total | 694 |
• Density | 37/sq mi (14/km2) |
ZIP codes | 47018, 47040 |
GNIS feature ID | 453166 |
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