Amherst, Ohio
City in Ohio, United States / From Wikipedia, the free encyclopedia
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Amherst (/ˈæmhərst/ AM-hərst)[5] is a city in Lorain County, Ohio, United States. It is located 28 miles (45 km) west of Cleveland within the Cleveland metropolitan area. The population was 12,681 at the 2020 census.[6]
See also: Amherst Township, Lorain County, Ohio
Quick Facts Country, State ...
Amherst, Ohio | |
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Nickname: Hurst | |
Motto: "Sandstone Center of the World" | |
Coordinates: 41°24′15″N 82°14′38″W | |
Country | United States |
State | Ohio |
County | Lorain |
Area | |
• Total | 7.14 sq mi (18.50 km2) |
• Land | 7.08 sq mi (18.35 km2) |
• Water | 0.06 sq mi (0.16 km2) |
Elevation | 646 ft (197 m) |
Population (2020) | |
• Total | 12,681 |
• Estimate (2023)[3] | 12,928 |
• Density | 1,790.09/sq mi (691.15/km2) |
Time zone | UTC-5 (Eastern (EST)) |
• Summer (DST) | UTC-4 (EDT) |
ZIP code | 44001 |
Area code | 440 |
FIPS code | 39-01798[4] |
GNIS feature ID | 1086498[2] |
Website | http://www.amherstohio.org/ |
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