1940 United States presidential election in Delaware
Election in Delaware / From Wikipedia, the free encyclopedia
The 1940 United States presidential election in Delaware took place on November 5, 1940, as part of the 1940 United States presidential election. Delaware voters chose three[2] representatives, or electors, to the Electoral College, who voted for president and vice president.
Main article: 1940 United States presidential election
Quick Facts All 3 Delaware votes to the Electoral College, Nominee ...
| ||||||||||||||||||||||||||
All 3 Delaware votes to the Electoral College | ||||||||||||||||||||||||||
---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| ||||||||||||||||||||||||||
County Results
Roosevelt 50-60%
| ||||||||||||||||||||||||||
|
Close
Delaware was won by incumbent President Franklin D. Roosevelt (D–New York), running with Secretary Henry A. Wallace, with 54.70% of the popular vote, against Wendell Willkie (R–New York), running with Minority Leader Charles L. McNary, with 45.05% of the popular vote.[3][4]