1868 United States presidential election in Delaware
Election in Delaware / From Wikipedia, the free encyclopedia
The 1868 United States presidential election in Delaware took place on November 3, 1868, as part of the 1868 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.
Main article: 1868 United States presidential election
Quick Facts Nominee, Party ...
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County Results
Seymour 50-60% 60-70%
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Delaware voted for the Democratic nominee, Horatio Seymour, over the Republican nominee, Ulysses S. Grant. Seymour won the state by a margin of 18%.
With 59% of the popular vote, Delaware would prove to be Seymour's fifth strongest state in terms of popular vote percentage after Kentucky, Louisiana, Maryland and Georgia.[1]