1860 United States presidential election in Minnesota
Election in Minnesota / From Wikipedia, the free encyclopedia
Dear Wikiwand AI, let's keep it short by simply answering these key questions:
Can you list the top facts and stats about 1860 United States presidential election in Minnesota?
Summarize this article for a 10 year old
The 1860 United States presidential election in Minnesota took place on November 6, 1860, as part of the 1860 United States presidential election. Minnesota voters chose four representatives, or electors, to the Electoral College, who voted for president and vice president.
| ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
County Results
| ||||||||||||||||||||||||||
|
Minnesota voted in its first ever United States presidential election, having been admitted as the 32nd state on May 11, 1858. The state was won by Illinois Representative Abraham Lincoln (Republican Party (United States)), running with Senator Hannibal Hamlin, with 63.44% of the popular vote, against Senator Stephen A. Douglas (D–Illinois), running with 41st Governor of Georgia Herschel V. Johnson, with 34.27% of the popular vote.
With 63.44% of the popular vote, Lincoln's victory within the state would be his second strongest victory in terms of percentage in the popular vote in the 1860 election after Vermont.[1] Minnesota would never vote Democratic until Franklin D. Roosevelt won it in 1932, 72 years later.