1828 United States presidential election in Georgia
Election in Georgia / From Wikipedia, the free encyclopedia
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The 1828 United States presidential election in Georgia took place on November 3, 1828, as part of the 1828 United States presidential election. Georgia voters chose 9 electors to the Electoral College, who voted for president and vice president.
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There were two Andrew Jackson tickets in Georgia representing the two different local parties. The Troup party won with 9,712 votes, beating the Clark (or Clarke) party which got 7,991 votes. John Quincy Adams was not nominated by any of the parties and came in third with only 642 votes. The state rejected returns from 10 counties and 8 others submitted none. Including the rejected returns, the total votes are Jackson (Troup) 10,508, Jackson (Clark) 8,854 and Adams, 642. Many sources have combined the vote when reporting the Georgia results, but this is legally incorrect.[1]
The Toup party ran Jackson with William H. Crawford for vice president but none actually voted for him, instead seven votes went to William Smith of South Carolina, a decision characterized as "throwing away seven votes on a man, not thought of by their constituents or by any of the other states." Two of the electors voted for the official running mate John C. Calhoun, who the Clark party ran as their running mate.[2]