Tennis at the 1968 Summer Olympics – Exhibition mixed doubles
1968 tennis event results / From Wikipedia, the free encyclopedia
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Since the 1968 Summer Olympics did not feature tennis as an official sport, two unofficial tournaments were held during the Games: a Demonstration tournament and an Exhibition tournament.[1]
Exhibition mixed doubles | |||||||||||||||||||||||||
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Tennis at the 1968 Summer Olympics | |||||||||||||||||||||||||
Final | |||||||||||||||||||||||||
Champions | Zaiga Jansone Vladimir Korotkov | ||||||||||||||||||||||||
Runners-up | Peaches Bartkowicz Ingo Buding | ||||||||||||||||||||||||
Score | 7–5, 6–4 | ||||||||||||||||||||||||
Events | |||||||||||||||||||||||||
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The Exhibition tournament was played from 24 to 26 October 1968 on the clay courts of the Chapultepec Sports Center in Mexico City, Mexico.[2] All matches were played at best-of-three sets; since the tiebreak rule wasn't implemented until the 1970s, a team had to win a set by a two-game margin in case of a 6–6 draw. Due to the short length of the tournament, no third-place match was played, and both semifinal losers received bronze medals.
Soviets Zaiga Jansone and Vladimir Korotkov won the tournament by defeating American Peaches Bartkowicz and West German Ingo Buding 7–5, 6–4 in the final. Brazilian Suzana Petersen and also Soviet Teimuraz Kakulia, alongside French Rosa María Darmon and Pierre Darmon, have won bronze medals.