Tennis at the 1912 Summer Olympics – Men's outdoor doubles
1912 tennis event results / From Wikipedia, the free encyclopedia
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The outdoor men's doubles competition at the 1912 Summer Olympics was part of the tennis program for the games. There were 42 players from 10 nations, comprising 21 teams.[1] Nations were limited to 4 pairs (8 players) each.[2] The event was won by South African team Harold Kitson and Charles Winslow, defeating Austrians Felix Pipes and Arthur Zborzil in the final. It was the first medal in the event for both nations. France earned its first men's double since 1900 as Albert Canet and Édouard Mény de Marangue defeated Jaroslav Just and Ladislav Žemla of Bohemia in the bronze-medal match.
Quick Facts Men's doubles tennis at the Games of the V Olympiad, Venue ...
Men's doubles tennis at the Games of the V Olympiad | ||||||||||
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Venue | Östermalms IP | |||||||||
Dates | 28 June – 5 July 1912 | |||||||||
Competitors | 21 teams (42 players) from 10 nations | |||||||||
Medalists | ||||||||||
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