1928 Wimbledon Championships – Women's doubles
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Elizabeth Ryan and Helen Wills were the defending champions, but Wills did not participate. Ryan partnered with Joan Lycett, but lost in the semifinals to Peggy Saunders and Phoebe Watson.
Quick Facts Women's doubles, Final ...
Women's doubles | |||||||||||||
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1928 Wimbledon Championships | |||||||||||||
Final | |||||||||||||
Champions | Peggy Saunders Phoebe Watson | ||||||||||||
Runners-up | Eileen Bennett Ermyntrude Harvey | ||||||||||||
Score | 6–2, 6–3 | ||||||||||||
Details | |||||||||||||
Draw | 40 (5 Q ) | ||||||||||||
Seeds | 4 | ||||||||||||
Events | |||||||||||||
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Main article: 1928 Wimbledon Championships
Watson and Saunders defeated Eileen Bennett and Ermyntrude Harvey in the final, 6–2, 6–3 to win the ladies' doubles tennis title at the 1928 Wimbledon Championships.[1][2]